1. Evaluate (3x + 6) ÷ [y3(x + 2)] if x = 2 and y = 1. Note the expression is 3(x+2)/(ył(x+2)); y is 1, so ył is 1; to evaluate, put in 2 for x. 2. Simplify the following expression: (16x+24)/8 + [2(y-3)-1]/[(27y-18x)/9]
Here's some of them. I got tired of doing inequalities 1. x > 2/3 or x < -2 2. 6/5, -2 3. -2 <= p <= 6 4. r not equal to 4 5. 1.25 < n < 3.75 6. t = 0,3 7. k < -1 or k > 1/3 19. 14,16,18 or 16
To solve these, I will call the distances u and v. In the x direction, I will call the distance ux and vx. In the y direction, I will call the distance uy and vy. The angles for u and v will be called
Systems 2 1. A, 2. D, 3. A, 4. D, 5. B, 6. B, 7. D, 8. C, 9. B, 10. C Systems 3 1. A, 2. B, 3. B, 4. B Systems 4 1. A 2. 6x+4y=-4, 6x-9y=30, subtract to get 17y=-34 so y=-2, x=2, 3. D, 4. D Systems
Hello, David. 1 3/10 + 3 2/5 The first step in this problem is to convert each mixed number into an improper fraction. To do this, first multiply each denominator by its respective whole number

©2012 About.com, a part of The New York Times Company. All rights reserved.