Questioner:Tommy Country:North Carolina, United States Category:Calculus Private:No Subject:calculus 1 Question: a) find an equation in slope-intercept form of the tangent line to the parabola
Firstly, your final answer should be 43.96, not 49.6 (I have verified this using a graphic calculator) Secondly, if the first integral of -(3(x^2)-8(x)) on (0,8/3) gives you zero, most likely you have
1. Evaluate (3x + 6) ÷ [y3(x + 2)] if x = 2 and y = 1. Note the expression is 3(x+2)/(ył(x+2)); y is 1, so ył is 1; to evaluate, put in 2 for x. 2. Simplify the following expression: (16x+24)/8 + [2(y-3)-1]/[(27y-18x)/9]
Here's some of them. I got tired of doing inequalities 1. x > 2/3 or x < -2 2. 6/5, -2 3. -2 <= p <= 6 4. r not equal to 4 5. 1.25 < n < 3.75 6. t = 0,3 7. k < -1 or k > 1/3 19. 14,16,18 or 16
To solve these, I will call the distances u and v. In the x direction, I will call the distance ux and vx. In the y direction, I will call the distance uy and vy. The angles for u and v will be called

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