Number Theory - Mathematics

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Name	Expertise	Status

Vijilant U.K. View Profile	I can answer questions in Spanish as well as English. Most questions on number theory, divisibility, primes, Euclidean algorithm, Fermat`s theorem, Wilson`s theorem, factorisation, euclidean algorithm, diophantine equations, Chinese remainder theorem, group theory, congruences, continued fractions.	Available Ask A Question View Past Answers
Chris U.S. View Profile	I am able to answer many questions related to number theory, including Fibonacci numbers, divisibility, primality, Fermat numbers, multiplicative and additive number theory, basic partition theory, combinatorics, generating functions, and algebraic number theory.	On Vacation returns 12/31/2008

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Recent Answers

2008-12-01 Number theory: Hello Heather I don't think your statement a^n+1=a^m2^p+1=a^2pm+1=b^m+1 is correct. It doesn't include any parentheses. a^n + 1 = a^(m*2^p) + 1 = (a^m)^(2^p) +1 = (a^(2^p))^m +1 Write b = a^(2^p)...

2008-11-18 Follow up question: Hello Bridget x^2 + 5x + 1 = 0 mod 47 5 is even so add 47 to get x^2 + 52x + 1 = 0 mod 47 Now you can complete the square. (x+26)^2 = 26^2-1 = 17 mod 47 You do the other one in the same way. There...

2008-11-18 Number Theory: Hello Bridget I think this is a copy of the answer you need Questioner: Jules Category: Number Theory Private: Yes Subject: Number Theory Question: I am so struggling with this. I have...

2008-11-17 mathmatics-number theory: Hello natraj I assume that you can use the quadratic residues theorem. Firstly 2 is a a special case. -3 = 1 mod 2. Now the odd primes (-3/p) = (-1/p)*(3/p). (-1/p) = (-1)^((p-1)/2) so =1 if p = 1...

2008-11-16 recurring decimals: Hello Dan This is a very interesting question, and I hadn't realised that before, so thank you. I will try to explain it, but haven't time to develop a rigorous proof. When we divide 1.000000.. by 7...

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