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Paul Klarreich

On Vacation
returns 11/15/2009
I can answer questions in basic to advanced algebra (theory of equations, complex numbers), precalculus (functions, graphs, exponential, logarithmic, and trigonometric functions and identities), basic probability, and finite mathematics, including mathematical induction. I can also try (but not guarantee) to answer questions on Abstract Algebra -- groups, rings, etc. and Analysis -- sequences, limits, continuity. I won't understand specialized engineering or business jargon.

Socrates

On Vacation
returns 11/29/2009
I can answer any questions from the standard four semester Calulus sequence. Derivatives, partial derivatives, chain rule, single and multiple integrals, change of variable, sequences and series, vector integration (Green`s Theorem, Stokes, and Gauss) and applications. Pre-Calculus, Linear Algebra and Finite Math questions are also welcome.

Ahmed Salami

Nigeria
Maxed Out
I can provide good answers to questions dealing in almost all of mathematics especially from A`Level downwards. I can as well help a good deal in Physics with most emphasis directed towards mechanics.

Sherry Wallin

U.S.
Maxed Out
I can answer most questions up though Calculus and some in Number Theory and Abstract Algebra.

Scott A Wilson

U.S.
Maxed Out
I can answer any question in general math, arithetic, discret math, algebra, box problems, geometry, filling a tank with water, trigonometry, pre-calculus, linear algebra, complex mathematics, probability, statistics, and most of anything else that relates to math.

Recent Answers

2009-11-08 Function Rules:

Penny~ Try plotting the ordered pairs (5,10), (10,5), (15,10), (20,15) to see what shape you get. I can tell you that you will get a parabola. You can plug values into the equation y = ax^2+bx +

2009-11-08 Pre-Calculus:

u= (1-0,-2-0) = (1,-2) v= (4-1,2--2) = (3,4) cos x = u dot v/|u||v| = 1(3) -2(4)/sqrt(1^2+(-2)^2)*sqrt(3^2+4^2) = [3-8]/sqrt(5)*sqrt(25) = -5/[5sqrt5] = -1/sqrt5 that is that cos x = -1/sqrt5 but you

2009-11-07 Ratio:

Hi Hamad~ I just viewed the video and he is a good math teacher. You want to do what he did with pure math and it is necessary to use some language in order to clarify what the variables represent

2009-11-07 Trig:

First things first. The sine of angle is a number but the inverse sine of a number is an angle. So you are hunting for the tangent of an angle. The first thing you need to do is decide what angle in between

2009-11-07 Algebra II.....please help me its urgent!!!:

Hi Krystal, 21) y - k = a(x + 3)² At (-5,1) 1 - k = a(-5 + 3)² = a(-2)² = 4a k = 1 - 4a At (1,7) 7 - k = a(1 + 3)² = a(4)² = 16a k = 7 - 16a Therefore, 1 - 4a = 7 -

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