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Patrick J. O'Neill

U.S.
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I can help with any basic math problem you have including ones from algebra. I can give you tips on how to do math quickly in your head.

Lynn Houston

U.S.
Available
I can answer questions in basic algebra and any grade school math.

Josh

Australia
Available
When I work through problems, I emphasize principles and key ideas which I believe are worth noting. I will try to answer questions in the following areas, but not at the advanced level. Algebra. Sequences & Series. Trigonometry. Functions & Graphs. Coordinate Geometry. Quadratic Polynomials. Exponentials & Logarithms. Basic Calculus. Probability, Permutations and Combinations. Mathematical Induction. Complex numbers. Physics problems.

Recent Answers

2009-11-20 cube:

The only way I know is with a lot of pencil work. You just whittle it down. 10^3 is 1000 so you know it's more than that. 20^3 is 8000, so you know it's between 10 and 20 and it's a little closer to

2009-11-20 algebra:

Going on the assumption that the problem is accurate as I applied the parentheses 5-(1 1/2)X=-9 5-(3/2)X=-9 multiply everything by 2 10-3x = -18 add 3x and 18 to both sides of = sign 10-3x +3x

2009-11-20 completing the square in quadratic equations,cubic equations,graphs:

Hi Richard, I'm glad you asked a follow-up. Regarding "completing the squares", let me try explaining it in another way. I'll focus more on the procedure this time. If you need to understand why something

2009-11-19 Percentages & Fractions:

I think what we looked at last time is not unrelated to the question that you now pose. Recapping on what we have done -- previously, we considered the problem of finding a multiplicative factor (X/Y)

2009-11-19 cube:

Let the cube root of 5000 be x. What this means is that x*x*x = 5000. This is not a pleasant number to work out in the head. To find x, may I suggest that you compute (5000)^(1/3) on a calculator.

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