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| Expert | Average Ratings | Expertise |
|---|---|---|
Patrick J. O'NeillU.S.
Available
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I can help with any basic math problem you have including ones from algebra. I can give you tips on how to do math quickly in your head. | |
Lynn HoustonU.S.
Available
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I can answer questions in basic algebra and any grade school math. | |
JoshAustralia
Available
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When I work through problems, I emphasize principles and key ideas which I believe are worth noting. I will try to answer questions in the following areas, but not at the advanced level. Algebra. Sequences & Series. Trigonometry. Functions & Graphs. Coordinate Geometry. Quadratic Polynomials. Exponentials & Logarithms. Basic Calculus. Probability, Permutations and Combinations. Mathematical Induction. Complex numbers. Physics problems. |
The only way I know is with a lot of pencil work. You just whittle it down. 10^3 is 1000 so you know it's more than that. 20^3 is 8000, so you know it's between 10 and 20 and it's a little closer to
Going on the assumption that the problem is accurate as I applied the parentheses 5-(1 1/2)X=-9 5-(3/2)X=-9 multiply everything by 2 10-3x = -18 add 3x and 18 to both sides of = sign 10-3x +3x
Hi Richard, I'm glad you asked a follow-up. Regarding "completing the squares", let me try explaining it in another way. I'll focus more on the procedure this time. If you need to understand why something
I think what we looked at last time is not unrelated to the question that you now pose. Recapping on what we have done -- previously, we considered the problem of finding a multiplicative factor (X/Y)
Let the cube root of 5000 be x. What this means is that x*x*x = 5000. This is not a pleasant number to work out in the head. To find x, may I suggest that you compute (5000)^(1/3) on a calculator.
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