You are here:
| Expert | Average Ratings | Expertise |
|---|---|---|
Dr. Nyayapati SwamiSingapore
Available
|
I can help you in solving first and second order differential equations. Questions must be at the Undergraduate level. <font color="red">Do not expect me to do all your homework.</FONT>. If you have a homework question with no clues on how to go about, I will only give you some pointers on solving them. | |
Scott A WilsonU.S.
Available
|
Most ordinary differential equations. |
Then it was (4-5x²)^(4/3). This is (f(x))^(4/3) where f(x) = 4-5x². The derivative is (4/3)•(f(x))^(1/3)•f'(x), and f'(x) = -10x. Putting the f'(x) out front and multipling th -10 by 4 gives us (-40/3)x•f'(x)•f(x)^(1/3)
This sounds like an exponential distribution with L=1/4 where L is for lambda. Since the distribution is f(x) = Le^(-Lx), the cumulative distribution is 1 - e^(-Lt) for x being between 0 and t.
This is a standard question and can be solved directly by applying the formulae. No special skills are needed to answer this question. I will just give you some clues and you need to work out the details
The equation is y" - 8y' + 18y = 4e^(4x) + 3x^3. The simplest solution that can be found would be y = Ae^(4x) + Bx³ + Cx² + Dx + C. This leads to y' = 4Ae^(4x) + 3Bx² + 2Cx + D. We then get y" = 16Ae^(4x)
Again, I' not quite sure this is right, but here goes. You can look at it and tell me what you think. If you get a better way to do it, let me know. Let L be litres and G be grams. The amount of
Answers by Expert:

©2009 About.com, a part of The New York Times Company. All rights reserved.