| Name | Expertise | Status |
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Abe Mantell
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| Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions! | Available
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eigensteve
U.S.
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| I have research experience working with ordinary differential equations. In particular, I can help with methods of solution, numerical integration, stability analysis and physical applications of ODEs. Dynamical systems and control theory are great. Also, differential equations arising from classical mechanics (Newton, Lagrange, Hamilton) interest me. | Available
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Dr. Nyayapati Swami
Singapore
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| I can help you in solving first and second order differential equations. Questions must be at the Undergraduate level. Do not expect me to do all your homework. If you have a homework question with no clues on how to go about, I will only give you some pointers on solving them. | On Vacation
returns 07/20/2009
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2009-06-06 Differential Equation, Solutions: 1. Re-written as: y'' + (x^2-1)/(x^2(x+1)) y' - y/(x^2(x+1)) = 0 . Singular points where x^2(x+1)=0...thus x=0 and x=-1 are singular pts. . Since lim (as x->0) x[(x^2-1)/(x^2(x+1))] DNE, x=0 is an...
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2009-06-03 soln for differential equation: The equation is separable: dP/(2 + 3P + P^2) = - dt Using partial fractions this can be written as [1/(P + 1)] - [1/(P + 2)] dP = - dt Integration now gives ln [(P + 1)/(P + 2) ] = -t +...
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2009-05-31 Maths2: Let y=e^(rx), so we get the characteristic equation: r^2-4r+4=0 ==> (r-2)(r-2)=0 ==> r=2,2 Repeated root, so the general solution is: y(x)=(A+Bx)e^(2x) Now impose the IC's: y(0)=0 ==> 0=(A+0)e^0...
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2009-05-22 mixing problem in differential equations: a) The tank will be full in 50min [Water enters at 5gal/min and withdrawn at 3gal/min, so the net increase is 2gal/min. Therefore for 100gal increase it will take 100/2=50min] b) At time t, the amount...
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2009-05-21 non linear differential equation: Try reducing to first order and then solve let v = dy/dx then d^y/dx^2 = dv/dx = (dv/dy)(dy/dx) = (dv/dy)v The equation will reduce to first order in v, y variables, which I believe would be solvable...
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