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Azeem Hussain

Canada
Available
  • Knowledgeability 9.85
  • Clarity of Response 9.80
  • Timeliness 9.82
  • Politeness 9.87
  • Total Questions 1177
 I can answer virtually any kind of question dealing with of Math 536 and below, my forte being in parabolic functions and analytical geometry. I'm currently learning Linear Algebra, and cannot answer questions that deal with subject matter more advanced than that.

Scott A Wilson

U.S.
Available
  • Knowledgeability 9.60
  • Clarity of Response 9.50
  • Timeliness 9.80
  • Politeness 9.60
  • Total Questions 80
 Whatever questions you ask except how to trisect an angle.

Recent Answers

2009-11-19 Trigonometry:

Symon, When looking for an angle, you need to use inverse trig operations. In this case, the angle will equal the arccosine of 6/20, or cos^(-1) 6/20. How high the ladder reaches on the building can

2009-11-18 Statements and Reasons help:

L is in the midpoint of KM, so KL = LM. M is in th midpoint of LN, so LM = MN. Taking both equalities together, KL = LM = MN. For Given: JL bisects KJM, m1=m3, Prove: JM bisects LJN I need to know

2009-11-10 question:

If the spere is fillable with water, the volume can be found by filling the spere with water and then measuring the overflow when the object is put back in. Have something below the sphere to catch the

2009-11-08 circle-octagon problem:

The height of a right triangle is 150cm. The base is the length of a side. The diameter of the circle is the hypoteneuse of that triangle. If a octagon is drawn, it can be seen that there are three

2009-11-05 geometry:

The measure of the angle is X. The angles compliment is 90°-X. The problem states that X = 3(90°-X). That works out to X = 270° - 3X. Add 3X to both sides and you get 4X = 270°. Divide both

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