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I have provided first hand support since `95 for Microsoft Office majoring in Word and Excel - support for all versions from 2 onwards
My background is in the insurance industry and call centre areas, but have been called upon to provide many varied solutions.
I'm educated to UK A level standard, but as I left school some 30 years ago that is rather irrelevent - university of life has provided more of a background!
| User | Date | K | C | T | P | Comments |
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| Shan | 11/22/09 | 10 | 10 | 10 | 10 | Thanks so much for this. It helps ..... |
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| Joe | 11/21/09 | 10 | 10 | 10 | 10 | Man, Aidan, thank you very much. . I'm ..... |
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The macro sounds fairly easy- it's basically going to be a for...next loop which puts in the values and copies the results to an output array - happy to write it for you, but might need slight guidance
Not a problem - you can use a COUNTIF function to determine the first row, and a sumif to give you the value, with an IF statement to handle the rest =if(countif($A$2:$A$100,a2)-countif(a2:$A$100,a2)=1
Not sure I have enough to go on in that at the MOMENT it doesn't sound like a lookup, simply an IF statement - but I suspect it WILL be a lookup - the easiest way at that point is to have A12NO
Excellent- your formula has a SLIGHT problem in that presumably the holiday continues in January, february etc - so these would produce a negative number with the formula as it stands =[hours left]+([hours
multiple lines is always going to be a problem as no function can program the lines, but you could seperate with commas - I have a custom function that will do this (with amendments) which you can see
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