Advanced Math/Expert Profile

Chen Min

On Vacation
returns 12/31/2016

All the conceptual questions, pure math & basic stats alike I am good at answering your algebra (including logarithm, functions, trigonometry) and geometry questions. I can also provide to you a firm understanding into basic calculus and other mathematical ideas and concepts. You can either ask questions in English or Chinese. Physics Qns that require rigorous math are also welcomed Important:Please avoid asking me questions related to economics.After all, I am only a secondary school student

Experience in the area

A lot of participation in Math Olympiad Competition with numerous awards (Not always gold, though) CMO Gold, SMO Silver, SPhO Gold


So far, nothing.

What do you like about this subject?

Exactness..No exceptions in its definition..Intricate but intriguing solutions to problems

What do you still hope to achieve/learn in this field?

Anything related to my future ambitions..

Something interesting about this subject that others may not know:


Something controversial or provocative about this subject

Even math has assumptions

Average Ratings

Recent Reviews from Users

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    K = Knowledgeability    C = Clarity of Response    P = Politeness
Donna02/24/11101010Thanks Chen, I went through all possibilites .....
Kenneth02/22/11101010Thanks for the reply!
Kenneth02/16/11101010Thanks for your reply!
Oliver01/27/11101010Thanks so much Chen. This one was .....
Oliver01/25/11101010Awesome! Thank you so much Chen - .....

Recent Answers from Chen Min

2015-01-05 Help:    To get inflexion point, differentiate your function twice and check when it is zero    becos: first derivative shows whether it's

2015-01-05 Mathematics Question:

The question asking for a slope, which is supposed to be dy/dx (and not dx/dy)    (in fact it is arbitrary to take x as independent variable and y the dependent, for example y = 2x + 1 can be rewritten

2011-03-15 Volume of a Cone:

Firstly, you get the arc length corresponding to the sector cut out: R(theta)  It's the circumference of the cone's base: so 2(pi)r=R(theta), r = R(theta)/2(pi), where r is the radius of the cone's base

2011-02-17 Finding the Point of Diminishing Return:

I wonder who gave you this question. It is clearly not solvable to me.    If you treat the two variables' relation as a function (shown as a curve in your axis), the PODR is at the point where dy/dx is

2011-02-16 Incomplete Calculation:

I don't quite understand your question.    If either y or z is replaced by a number, then there will be only one unknown (variable), and the equation will be solvable, and most likely has a single unique


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