Advanced Math/Expert Profile

Socrates

On Vacation
returns 11/29/2009
Expertise

I can answer any questions from the standard four semester Calulus sequence. Derivatives, partial derivatives, chain rule, single and multiple integrals, change of variable, sequences and series, vector integration (Green`s Theorem, Stokes, and Gauss) and applications. Pre-Calculus, Linear Algebra and Finite Math questions are also welcome.

Experience in the area

Ph.D. in Mathematics and many years teaching undergraduate courses at three state universities.

Education/Credentials

B.S. , M.S. , Ph.D.

Average Ratings

Recent Reviews from Users

Read More Comments

    K = Knowledgeability    C = Clarity of Response    T = Timeliness    P = Politeness
UserDateKCTPComments
Kenneth10/04/09101010Thanks for the reply and answer!
Xue Ting08/30/09101010 
Anthony05/21/0910101010thanks Socrates
bina03/26/09101010 
Sombra02/22/0910101010Thank you so much, you made it .....

Recent Answers from Socrates

2009-09-30 Mathematical Expression:

$15 for 10 people for 10 days would work out to .15 per person per day , so that's not right $150 for 10 people for 10 days would work out to $1.50 per person per day , so this is one posible answer

2009-08-27 Family of functions?:

" x + x^2 + x^3 + ....+ x^n approaches x/(1-x)" x + x^2 + x^3 + ....+ x^n + ..... is a geometric series , with sum x/(1-x) , you should have seen this before you studied Mclaurin series. If not

2009-08-26 Family of functions?:

(Fn(x))/x = 1 + 4x + 9x^2 + ....+ (n^2) (x^(n-1)) = (x + 2x^2 + 3x^3 +....+ nx^n)' = ((x)( 1 + 2x + 3x^2 + ...+ nx^n-1))' = ((x) (x + x^2 + x^3 + ....+ x^n)' )' Since x + x^2 + x^3 + ....+

2009-07-22 Precalculus:

Your work is correct as far as it goes. The left side is cos A + 1 , as you have found . But the right side is sin^2/1-cos A = (1 - cos^2 A )/ (1 - cos A ) Factor the numerator (1 - cos^2 A )

2009-05-21 math:

The common denominator is 12ab (2a+3b)/3a = (4b)(2a+3b)/12ab = (8ab + 12b^2)/12ab (a-2b)/4b = (3a)(a-2b)/12ab = (3a^2 - 6ab)/12ab (a^2+b^2)/ab = (12a^2+12b^2)/12ab So (2a+3b)/3a - (a-2b)/4b

 

Ask A Question

All Answers

Answers by Expert:


Ask Experts

Volunteer


©2009 About.com, a part of The New York Times Company. All rights reserved.