Advanced Math/Expert Profile

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Recent Answers from Socrates

2011-11-22 convergence of series:

Compare n!/n^3   to 1/n    n!/n^3 > 1/n    (n-1)!/n^2 > 1/n    (n-1)!/n > 1     (n-2)!  (n-1)/n  > 1    Since (n-1)/n goes to 1 as n goes to plus infinity,  and (n-2)! goes to plus infinity , the left

2011-09-18 algebra:

1)     Since complex zeros for polynomials with real coefficients always occur in conjugate pairs, 1+i must also be a zero.    Thus , 2√3 , 1+i , 1-i must all be zeros.    Note that (x-(1+i))(x-(1-i))

2011-08-19 Are My Answers Correct?:

The first two are ok.    Look what you have sent me for the third problem:    "Now, on Problem 3, I need a little assistance:  Determine the truth value of the statement when p is T, q is F, and r is F:

2011-07-18 Find the length of an arc:

s=rθ , where θ is the radian measure of the angle , r is the radius and s is the arc length      1)   s = (17.2)(π/3) = (17.2)(1.04719755)= 18.01 inches        3)   You must convert 72°

2010-10-27 Pure maths:

To find C we want the zeros of y=-2x^2+6X-4.  Solving 0 = -2x^2+6X-4 , we get x=1 or x=2  , so C=(2,0)    To find the normal line to the parabola at C = (2,0) , we need the slope of the tangent at x =