Advanced Math/Expert Profile

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Recent Answers from Ahmed Salami

2012-02-08 trig:

Hi Tom,  (1 - cosA)(1 + secA) = 1 + secA - cosA - cosA.secA  = 1 + (1/cosA) - cosA - cosA(1/cosA)  = 1 + (1/cosA) - cosA - 1  = (1/cosA) - cosA  = (1 - cos²A)/cosA  But remember the identity; cos²A + sin²A

2012-02-04 Pradeep's question - need clarification:

Hi Kelly,  As i mentioned in the original solution there are different variations of the normal distribution table but they serve the same purpose in the end. I have attached two different tables to this

2012-01-17 Statistics:

Hi Pradeep,  We know that z for a value X in a distribution with mean μ and standard deviation σ is  z = X - μ / σ  So, at X = 48  z = (48 - 43.4)/σ  = 4.6/σ  From tables

2011-12-24 Sequence and divisibility:

Hi James,  If the first term of an arithmetic sequence is 3p+5 and its common difference is 2, then the nth term (or last term) is given by;  T(n) = (3p+5) + (n-1).2  = 3p + 5 + 2n - 2  = 3p + 2n + 3

2011-12-19 calculus - Advanced level mathematics:

Hi Anurag,  For y = 2e^(1-2x), the area from x = 0 to x = ln(2) is  A = ∫2e^(1-2x) dx   from x = 0 to ln(2)  = [-e^(1-2x)]   from x = 0 to ln(2)  = [-e.e^(-2x)]   from x = 0 to ln(2)  = [-e.e^(-2ln(2))]