You are here:

Advanced Math/Expert Profile


Ask A Question

Expertise

I can provide good answers to questions dealing in almost all of mathematics especially from A`Level downwards. I can as well help a good deal in Physics with most emphasis directed towards mechanics.

Experience in the area

Aspiring theoretical physicist. I have been doing maths and physics all my life.

Education/Credentials

I teach mathematics and engineering physics.

Average Ratings

Recent Reviews from Users

Read More Comments

    K = Knowledgeability    C = Clarity of Response    P = Politeness
UserDateKCPComments
Ndawana Blessing07/04/16101010Well explained. Thank you so much.
AB04/19/16101010Thanks
Kenneth02/03/16101010Thanks for the reply and information!
Kenneth11/26/15101010Thanks for the follow-up reply!
Kenneth11/25/15101010Thanks for the reply and explanation!

Recent Answers from Ahmed Salami

2016-07-04 A level Maths. remainder theorem:

Hi Ndawana,  From the information provided about the remainders when f(x) is divided by each of x-3 and 2x-1, we know that f(3) = -9 and f(1/2) = -6.  Since the product (x-3)(2x-1) is quadratic then the

2016-04-19 Relations( concerning sets):

Hi AB,    The modulus of a complex number z = a + bi is given by the positive value of  |z| = √(a + b)    So, for x = 2 + 3i  |x| = √(2 + 3) = √13  which is not the same as 13, and

2016-03-19 help:

Hello Apsara,  The first thing you need to know about percentages is that they are just a way of comparing two quantities to each other. So, 60% of 180 is just a number such that if you compare the size

2016-01-29 Unit Rate:

Hi Kenneth,  Yes, the inverse relationship means that you can't divide in that sense. In this case, the number of pipes multiplied by the time it takes to drain the tank is a constant, assuming pipes of

2015-11-25 Compound Proportions:

Hi Kenneth,  In cases like this it would be unlikely that all the quantities would be directly proportional, but it would be correct to perform appropriately similar operations on those that are directly

 

Ask A Question

Advanced Math

All Answers


Answers by Expert:


Ask Experts

Volunteer


©2016 About.com. All rights reserved.