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Expert Profile: Steve Holleran

Expertise:  I can help with all math questions from basic math to Calculus. Whether it`s consumer questions, or questions from high school or college students, I have probably dealt with it at some time in my career.

Experience in the area
33 years teaching experience in NJ public schools

Education/Credentials
B.S. Mathematics : Wake Forest University 1972 M.S. Mathematics : Monmouth University 1981

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Average Ratings
Prestige Points: 7670
Knowledge   9.91   Best of the best
Clarity of Response   9.90   Best of the best
Timeliness   9.86   Best of the best
Politeness   9.96   Best of the best
Number Of Questions
(in Past 24 Hours)
0
Max Questions to be Asked
(in 24 Hour period)
5
Total Questions
(since joining AllExperts)
944
Recent Reviews from Users
KnowlClarityTimePolitenessDate
1010101006/04/08
1010101005/30/08
101005/30/08
1010101005/26/08
1010101005/25/08
User Comments
Thank you so much steve you were very helpful
(cierra on 06/04/08)
Thanks for helping me!
(Cruz on 05/30/08)
Thanks
(Max on 05/30/08)
Thanks Steve!!.. this parametric stuff sure is tricky
(vince on 05/26/08)
Thak you very much Steve , this will help me alot in my exam!! thank you
(william on 05/25/08)
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Recent Answers from Steve Holleran
2008-05-30  Powers Hi Kirk, Well, if your calculator doesn't even have a power key, you can't do this without using tables of logarithms. To compute your example, 1.33^(0.2), you'd have to proceed like this:...
2008-05-29  Sequences Hi Patrick, Okay, here's what I see: You have an arithmetic sequence that looks like : 1 , 1+d, 1+2d, ... The nth term is 1 + (n-1)d, so term 10 is 1 + 9d and term 34 is...
2008-05-28  Simultaneous equations Hi Daryl, Your quadratic formula work is fine, but the trouble is being caused by a sign mistake early on: y = 11x + 3 y = 4x^2 so 4x^2...
2008-05-28  logarithms Hi Max, 1. Do you mean here that you want D = cu rt(V / .5236) and V = 100? If so, the you have log D = log [cu rt(100/.5236)] log D = log[(100/.5236)^(1/3)]...
2008-05-28  Sequences Hi Patrick, I think we need to use a formula here. The question is : 2^1 * 2^2 * 2^3 * . . . * 2^n = 2^210 so, when you multiply bases , you add exponents, and you have 2^(1...
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