You are here:

Advanced Math/Expert Profile

Steve Holleran

U.S.
On Vacation
returns 12/31/2009
Expertise

I can help with all math questions from basic math to Calculus. Whether it`s consumer questions, or questions from high school or college students, I have probably dealt with it at some time in my career.

Experience in the area

33 years teaching experience in NJ public schools

Education/Credentials

B.S. Mathematics : Wake Forest University 1972 M.S. Mathematics : Monmouth University 1981

Average Ratings

Recent Reviews from Users

Read More Comments

    K = Knowledgeability    C = Clarity of Response    T = Timeliness    P = Politeness
UserDateKCTPComments
Kenneth12/22/0810101010Thanks
Kenneth12/19/0810101010Thanks for the reply and information!
Sheryl10/04/0810101010 
QiWarm10/02/08101010thnks a million..its helped me to .....
Randy10/01/0810101010Fast Reply !!! Thanks.

Recent Answers from Steve Holleran

2009-05-22 Infinite geometric series:

Hi Jess, Okay, an infinite geometric series will have a sum if the ratio (r) between successive terms is between -1 and 1 (another way of saying this is if its absolute value is between 0 and 1).

2008-12-17 Percentages & Interest:

Hi Kenneth, It's really not that hard to do it algebraically: Let x = amount at 5%, then (30,000 - x) = amt at 2% Since I = PR, 1200 = .05x + .02(30,000 - x) 1200 = .05x + 600 - .02x

2008-11-02 Integration:

Hi Eliza, for the first one, I don't think you want to integrate at all. You should apply the Closed Interval Test for extrema: On a closed interval, a continuous function could have max / min

2008-10-02 Partial fraction:

Hello, I think it goes like this: (x^2-x)/(x^2+3)(x^2+2) =(Ax + B)/(x^2 + 3)+(Cx + D)/(x^2+2) x^2 - x = (Ax + B)(x^2+2) + (Cx + D)(x^2 + 3) x^2 - x = Ax^3 + Bx^2 + 2Ax

2008-09-30 Demand Equation:

Hi Tino, From the information you've given, you have two points of information, in the form (x, p): (42, 20) and ( 52, 10) from these you get the slope of the function m = (20

 

Ask A Question

All Answers

Answers by Expert:


Ask Experts

Volunteer


©2009 About.com, a part of The New York Times Company. All rights reserved.