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I can answer any question in general math, arithetic, discret math, algebra, box problems, geometry, filling a tank with water, trigonometry, pre-calculus, linear algebra, complex mathematics, probability, statistics, and most of anything else that relates to math.
Experience in the area; I have tutored people in the above areas of mathematics for almost two years in AllExperts.com. I have tutored people here and there in mathematics ever since I received a BS degree almost 25 years ago. I tutored at OSU in the math center for all six years I was there. Most students offering assistance were juniors, seniors, or graduate students. I was allowed to tutor as a freshman. I tutored at Mathnasium for well over a year. I worked at The Boeing Company for over 5 years. I received an MS degreee in Mathematics from Oregon State Univeristy. The classes I took were over 100 hours of upper division credits in mathematical courses such as calculus, statistics, probabilty, linear algrebra, powers, linear regression, matrices, and more. I graduated with honors. Past/Present Clients: College Students at Oregon State University, various math people since college, over 2,000 people ion the PC from the US and rest the world.
My master's paper was published in the OSU journal. The subject of it was Numerical Analysis used in shock waves and rarefaction fans. It dealt with discontinuities that arose over time. They were solved using the Leap Frog method. That method was used and improvements of it were shown. The improvements were by Enquist-Osher, Godunov, and Lax-Wendroff.
Master of Science at OSU with high honors in mathematics. Bachelor of Science at OSU with high honors in mathematical sciences. This degree involved mathematics, statistics, and computer science. I also took sophmore level physics and chemistry while I was attending college. On the side I took raquetball, but that's still not relevant.
I earned high honors in both my BS degree and MS degree from Oregon State. I was in near the top in most of my classes. In several classes, I was first. I graduated with well over 50 credits in upper division mathematics.
My clients have been students at OSU, people nearby, and friends with math questions, and several people every day on the PC. Just like you.
I do it all the time and sometimes in my dreams. Now 11*11*11*11*11*11 = 1,771,561. 1,771,561*11 = 19,487,171. Let me see 19,487,171*11 = 214,358,881. Now 214,358,881*11 is ...uh... 2,357,947,691.
I desire to learn even more about math and find new approaches to old problems.
The numbers 1 and 2 lead to 5 in two different ways. First, use the numbers 1 and 2 to makes 12, but rather than base 10, take base 3. That is 1*3 + 2 = 5. Second, square them and add them together. This leads to 1^2 + 2^2 = 5.
Someone once asked me if 728 = 9^3 - 1^3. I said, yes, but did you know that 728 = 12^3 - 10^3? I don't know if that's provocative...
| User | Date | K | C | T | P | Comments |
|---|---|---|---|---|---|---|
| Evelyn | 11/05/09 | 10 | 10 | 10 | 10 | Thanks Scotto! |
| Gayle | 11/01/09 | 10 | 10 | 10 | 10 | I appreciated the help and clarity of ..... |
| Pinto | 11/01/09 | 10 | 10 | 10 | 10 | Ah, ok I see, I forgot the ..... |
| Asad | 10/31/09 | 10 | 10 | 10 | 10 | Thanks |
| Cindy | 10/30/09 | 10 | 10 | 10 | 10 | Thank you for the help! |
If a - 1/a = 6, then multiply the entire equation by a. This gives a² - 1 = 6a, or a² - 1 - 6a = 0, which is the same as a² - 6a - 1 = 0. This can be solved with the quadratic equation. The answer
I put the answer in another file for you. The element that is in bold is what the row that it is on is mutiplied by. The other elements in the first column are what to mutiplly the row with a bold element
1a) Make one side of a right triangle as the rest of the way to first d. Make the other side the path to second s. Make the hypoteneuse the distance to second c Known: d²(t) + s² = c²(t). Differentiate
// a program to find the height of a tree #include <stdio.h> #include <math.h> void main() { float pi = 3.1416; float B = 15.5; // angle to the top in degrees float Brad = B*pi/180
Pascal's Triangle: Each row is found by the sum of two elements above it. On the edge, it is always 1. 5 : 1 5 10 10 5 1 6 : 1 6 15 20 15 6 1 7 : 1 7 21 35 35 21 7 1 10 : 1 10 45 120
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