I will answer any c language programming and syntax questions.
I have almost a decade of c programming experience.
I have a bachelor of science degree and several years of industry experience.
|Jessica||05/09/15||10||10||10||Thank you! I never thought to call .....|
|Kuridi||04/30/15||10||10||10||Thanks for clarification Tony, the problem is .....|
|nahian||03/23/15||7||5||10||good job brother|
Hi Kuridi, The problem is you are accessing out of bounds array indexes. "mat" is a 6x3 character array. The maximum indexes are 5 and 2. Your loops go from 0 to 6, and 0 to 3, which are outside the
Hi Ben, uint8_t is an unsigned eight bit type. The array variable in the code snippet you posted is a pointer to a uint8_t type. uint8_t and char are similar because they are both one byte in size.
Hi Archit, The free function expects a pointer to allocated memory. You might not be passing the correct type to free. <code> void free(void *ptr); The free() function frees the memory space
Hi Erin, "int *p" is a pointer to an integer. "&x" is the address of "int x". "*p" dereferences the pointer. I hope the following example code helps you understand how this works. <code> //example
You are passing the wrong type to printf. The code you have written will cause the following issue:
format ‘%d’ expects argument of type ‘int’, but argument 2 has type ‘int *’ Please