Aeronautical Engineering/Expert Profile


Ask A Question

Expertise

Aeronautics, Fluid Mechanics, Aeroacoustics, Noise Control, Muffler Design, Wind Tunnel Research.... I know nothing about India - do not ask about schools, jobs, application requirements, career choices, etc. for India. Please, no text message verbiage; I prefer full words in full sentences. Thanks.

Experience in the area

38 years as research engineer at NASA

Publications

AIAA, NASA

Education/Credentials

B.S. and M.S. Aeronautical Engineering - U. of Washington Graduate work Standford U.

Awards and Honors

AIAA Associate Fellow (American Institute of Aeronautics and Astronautics)

Average Ratings

Recent Reviews from Users

Read More Comments

    K = Knowledgeability    C = Clarity of Response    T = Timeliness    P = Politeness
UserDateKCTPComments
Vincent10/27/0910101010 
Richard10/27/0910101010Thank you Paul you've been most helpful .....
shalini10/14/091010 
sarah10/13/0910101010Many thanks. It's always a little daunting .....
M.Ramasamy10/06/0910101010thank you sir.i was totally confused .....

Recent Answers from Paul Soderman

2009-11-06 rockets?:

Jane Newton showed that the rocket thrust can be equated to its mass times acceleration, or more accurately to the time rate of change of momentum. A basic physics book can explain that in detail.

2009-11-05 Gas pressurized vessel:

Russell Assuming ambient temperature, the ideal gas laws indicate that your vessel would contain 0.27 lb of air and would expand to about 6115 in^3 at atmospheric pressure. But the velocity and time

2009-11-04 Aeroplane/ rocket lift:

Soumen You need to study physics as it pertains to Newton's laws. The rocket get thrust in space by expelling high velocity gases out the nozzle. Newton explains how that creates a reaction force and

2009-11-02 Aeroplane/ rocket lift:

Soumen The devil is in the details. But essentially, a wing with the proper shape, angle of attack, and airspeed will develop surface pressures that when integrated equal lift that counters the weight

2009-10-27 Bypass Ratio:

An engine with a bypass ratio of 2 will pass 2 kg/s of air through the fan for every 1 kg/s through the core. If you know the density and velocity of the two exhausts you could compute the thrust as:

 

Ask A Question

All Answers

Answers by Expert:


Ask Experts

Volunteer


©2009 About.com, a part of The New York Times Company. All rights reserved.