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Geometry/Expert Profile


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Expertise

Whatever questions you ask except how to trisect an angle.

Experience in the area

I have been assisting people in Geometry since the 80's.

Education/Credentials

MS at Oregon State, BS at Oregon State

Awards and Honors

I was the outstanding student in high school in the area of geometry and math in general.

Past/Present Clients

Around 3000 people, mostly in math, with almost two dozen in geometry.

What do you like about this subject?

It is an area of mathematics that I sometimes think is acute are to work with. My knowledge of it is quite obtuse. I bisect the questions down until I can answer each piece. Sometimes I go and use the complement to the question.

What do you still hope to achieve/learn in this field?

To offer assistance to several people, including you.

Something interesting about this subject that others may not know:

There are the same number of π radians in a circle as there are eggs most have for breakfast: 2. π almost looks like a pie ... you know, two sides and a top that overlaps the edges.

Something controversial or provocative about this subject

Many people have said geometry, but who have you heard say, "Gee, I'm a tree" ... We may think about the circle found in a trunk and measure the angles, but the relation stops there.

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Recent Reviews from Users

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    K = Knowledgeability    C = Clarity of Response    T = Timeliness    P = Politeness
UserDateKCTPComments
Abby11/19/09101010 
Nathan11/01/0910101010Very please with this explanation. Thanks!
Nathan11/01/0910101010This answer was clear and concise, and .....
Rafay10/15/09 
Bella10/03/091010This guy is very nice and intelligent .....

Recent Answers from Scott A Wilson

2009-11-18 Statements and Reasons help:

L is in the midpoint of KM, so KL = LM. M is in th midpoint of LN, so LM = MN. Taking both equalities together, KL = LM = MN. For Given: JL bisects KJM, m1=m3, Prove: JM bisects LJN I need to know

2009-11-10 question:

If the spere is fillable with water, the volume can be found by filling the spere with water and then measuring the overflow when the object is put back in. Have something below the sphere to catch the

2009-11-08 circle-octagon problem:

The height of a right triangle is 150cm. The base is the length of a side. The diameter of the circle is the hypoteneuse of that triangle. If a octagon is drawn, it can be seen that there are three

2009-11-05 geometry:

The measure of the angle is X. The angles compliment is 90°-X. The problem states that X = 3(90°-X). That works out to X = 270° - 3X. Add 3X to both sides and you get 4X = 270°. Divide both

2009-10-31 Geometry Story Problem:

Give one of the two sides that are equal length x. The length of the other side that is the same length is also x. The length of the third side is x/2. Add them up and we get x + x + x/2 = 5x/2.

 

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