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Geometry/Expert Profile

Azeem Hussain

Canada

Available

Expertise

I can answer mostly any kind of question dealing with of Math 536 and below, my forte being in parabolic functions and analytical geometry.

Experience in the area

Drop-in tutor at Champlain College since 2010. I am neither a professor nor a teacher of this subject. I am merely a student who is good at mathematics and enjoys being of service to his community. I frequently tutor people in math and the results are usually great.

Education/Credentials

Presently enrolled in Materials Engineering at McGill University. Diploma of Collegiate Studies; Pure and Applied Science, Champlain College Saint-Lambert. Diploma of Secondary Studies from Chambly Academy High School. Being a Quebecer, I am fluent in English and French and can respond to questions easily in both languages.

Average Ratings

Recent Reviews from Users

User	Date	K	C	P	Comments
SuperGeek	01/04/12	8	10	7
saadia	12/20/11	8	7	10
Kim	12/20/11	10	10	10	N/A
kevin	12/03/11	10	10	10	thanks for the informative, clear and thorough .....
kevin	11/29/11	10	10	10	thanks for the clear and informative answer .....

Recent Answers from Azeem Hussain

2012-02-02 Dimensions of a Compound shape with only the area:

Hey Chris, For a Norman window, the side of the square is equal to the diameter of the semicircle. We can therefore represent the area of each part in terms of a single parameter, x. This means we

2012-01-26 Distance Between Point and Line:

Hi Nour, The shortest distance is the perpendicular distance. This can be computed by taking the orthogonal projection between H and a point on the cable onto a vector consisting of the cable itself

2012-01-03 Pythagorean Triples:

Hey SuperGeek, There are two options: (1) Both sides are legs (2) The longer side is the hypotenuse and the other is a leg. For case (1) to hold, we need 24²+51²=[perfect square]. For case (2)

2011-12-14 Congruency Proof:

Hi Kim, It is given that angle BAD is congruent to Angle CAD and therefore triangles BAD and CAD are congruent by AAS congruency. AD bisects BC is equivalent to saying AD and BC have the same measure

2011-12-13 Geomtry Using Similarity:

Hi Angel, Once you've converted all measurements to the same units, divide the width of the wall by the width of the mural. Then divide the height of the wall by the height of the mural. Take whichever

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