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- Scott A Wilson

Any algebraic question you've got. That includes question that are linear, quadratic, exponential, etc.

I have solved story problems, linear equations, parabolic equations. I have also solved some 3rd order equations and equations with multiple variables.

Documents at Boeing in assistance on the manufacturiing floor.

MS at math OSU in mathematics at OSU, 1986. BS at OSU in mathematical sciences (math, statistics, computer science), 1984.

Both my BS and MS degrees were given with honors.

Students in a wide variety of areas since the 80's; over 1,000 of them have been in algebra.

I like that the solutions are either right or wrong. I also like the fact that they are easy to get to in most cases.

Well, I know expansions to (a+b)^2, (a+b)^3, (a+b)^4, (a+b)^5, and (a+b)^6, but that is only the start. I desire to know even more on pi than only 60 places, more on root two two ten places, more than 2^10= 1,024, 2^20 = 1,048,576, or 2^30 = 1,073,741,834, more that e = 2,71828182845905... etc.

Did you know that parabolas have zero, one, or two solutions? Of course, you most likely will know this after taking it awhile.

Some say 1/0 is meaningless, but others say that its infinity.

User | Date | K | C | P | Comments |
---|---|---|---|---|---|

Prashant S Akerkar | 07/29/16 | 10 | 10 | 10 | Dear Prof Scott Thanks. Prashant |

Prashant S Akerkar | 03/10/16 | 10 | 10 | 10 | Dear Prof Scott Thanks. Thanks & Regards ..... |

Prashant S Akerkar | 03/10/16 | 10 | 10 | 10 | Dear Prof Scott Thanks. Thanks & Regards ..... |

Chris | 02/02/16 | 10 | 10 | 10 | This guy knows his stuff! Congrats! Chris |

Chris | 01/31/16 | 10 | 10 | 10 | Thanks, Scott, your reply is much ..... |

An inequality is written if one side is known to be less than the other. For example, 1<3, which is read as, "one is less than three." To see this, subtract 1 from both sides and you get 0 < 2,

Once we know the parabola in the form of y = ax˛ + bx + c, it can be done. The y intercept is found by putting x=0, and the result is y = c. To get these points, take the values as (x1,y1), (x2,y2)

Yes, it is possible. However, it is not very likely. I'll assume that the election has a 50-50 chance of voting for two choices. Let's suppose that only 20 people voted on something. To get the

Any number in the complex number system can be expressed as a+bi. If we take the inverse of a+bi we get 1/(a+bi). If this is multiplied in the numerator and denominator by a-bi, the result is (a-bi)/[(a+bi)(a-bi)]

If the current close is close to the lowest low when compared to how close the highest high is to the lowest low, the percentage will be low. Since I don't believe the current close can exceed the highest

Algebra

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