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Scott A Wilson

U.S.

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Expertise

Any algebraic question you've got.

Experience in the area

story problems, solving equations, quadrilateral equation, multiple variables

Publications

documents at Boeing

Education/Credentials

MS at math OSU, BS at OSU in math

Awards and Honors

both degrees were given with honors

Past/Present Clients

students from all over since the 80's; over 1,000 in algebra

What do you like about this subject?

I like that the solutions are right or not and easy to get to in most cases.

What do you still hope to achieve/learn in this field?

Well, I know expansions to (a+b)^2, (a+b)^3, (a+b)^4, (a+b)^5, and (a+b)^6, but I hope to know more. I desire to know even more on high than only 60 places.

Something interesting about this subject that others may not know:

The lines y = mx + b has slope m and cross the y axis at x. Parabolas of the form ax^2 + bx + c = 0 have two solutions, x = (-b±√(b²-4ac)/(2a). Then again, most taking algebra know this after taking it awhile.

Something controversial or provocative about this subject

It only applies to lines, but wouldn't it be nice if others could be turned over and taking the negative of? It would give them a whole new slope on life. One that is at right angles with there current slope.

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Recent Reviews from Users

User	Date	K	C	T	P	Comments
Sara	11/24/09	10	10	9	10
Lori	11/22/09	10	10	10	10	Thank you very much for helping me .....
MUMTAZ	11/19/09	10	10	10	10	Thanks for giving me such a valuable .....
Asad	11/14/09	10	10	10	10	Thank you
Kedean	11/13/09	10	10	8	10	Thank you Scott the answer is a .....

Recent Answers from Scott A Wilson

2009-11-21 Algebra II:

The problem is √(8a^9)/√(b^3). It is known that √8 = √4√2 = 2√2. It is known that √a^9 = √a^4√a = a²√a. It is known that /√b^3 = √

2009-11-20 variables on both sides:

The parenthises mean to multiply what is on the outside by each element in the indside. Thus, our equation becomes 4y + 4 = 7y - 14. Subtracting -7y from both sides to put the y's on the left gives

2009-11-17 Variation and problem solving:

It is said that x = Ay/√z. Putting in x=5/2, y=2, and z=16 give us 5/2 = 2A*(1/√16) = 2A/4 = A/2. Since 5/2 = A/2, it cam be computed that 5=A. The equation is x = 5y/√z, so put

2009-11-11 ap calculus ab:

4. This is a product rule. That's y = f(x)g(x) where f(x)=x and g()=secx. The derivatives are f'(x)=1 and g'(x)=secx•tanx. The final formula for y' is y = fg' + fg'. 9. Here we have y=f(x)/g(x)

2009-11-11 Enhance my understanding, please..:

Extraneous solutions arise when we solve the problem by multiplying by some expression that cancels a term in the denominator. Once the problem has been solved, an extra solution is gotten that really

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