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- Frederick Koh

Singapore

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I can answer questions concerning calculus, complex numbers, vectors, statistics , algebra and trigonometry for the O level, A level and 1st/2nd year college math/engineering student.

More than 7 years of experience helping out in various homework forums. Latest presence is over at http://www.thestudentroom.co.uk/. You can also visit my main maths website http://www.whitegroupmaths.com where I have designed "question locker" vaults to store tons of fully worked math problems. A second one is currently being built. Peace.

IEEE(Institute of Electrical and Electronics Engineers )

Former straight As A level student from HCJC (aka HCI); scored distinctions in both C and Further Mathematics B Eng (Hons) From The National University Of Singapore (NUS) B Sc (Hons) From University of London External (Grad Route)

Hi Jimmy, The problem you suggested is rather interesting. Trying to crack things apart by brute force manipulation will probably not get you anywhere since it involves both conventional algebraic

[(y^ 1/2)/(x^ 3/4) - (x^ 5/4)/(y^ 3/2)]^4 = {(y-x^2)/ [(x^ 3/4)(y^ 3/2)] }^4 (Combine both terms to achieve a common denominator) = (y-x^2)^4 * 1/[(x^ 3/4)(y^ 3/2)] }^4 = (y-x^2)^4 * 1/[(x^

Total amount of gold in all 5 rings = 90/100 * 18 * 5 =81 g Total amount of silver in all 5 rings = 10/100 * 18 * 5 =9 g Let the required amount of silver to be added to dilute the gold content to

Typically, if you are required to discover the roots of a cubic equation via factorization, the equation would be designed such that the student can at least discover a root via trial and error. Such a

Factor theorem can be used to solve this. If we substitute x= 2/3 into 18x^(3) - 33x^(2) + 5x + 6, we get 18*(8/27) - 33* (4/9) +10/3 +6 = 16/3 - 44/3 +10/3 +6 = 0 Hence, 3x-2 is a factor of the

Algebra

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