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| User | Date | K | C | T | P | Comments |
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The first thing you can do is divide by 2 to get q^2-10q = 500/q Next, multiply each term by q to get q^3-10q^2 = 500 You can't factor it so re-write it f(q) = q^3-10q^2-500 Put in some value for q
Here's some of your answers 1. e^4.61 = 100 3. ln(1097) = 7 ln8 -ln2 = ln4 ln7 +0.5ln9 = ln(21) ln(1/x) = 2, x = 0.1353 e-x = 3, x = -0.2817 1/e^x = 7, x = =1.946 3e^(2x+2) = 50, x = 0.407 1.
The easiest way to answer your questions is to plot the parabola. For y = 0, x = -3 Put in y = +/- 1, +/- 2, +/- 3. calculate the corresponding values for x and plot x,y for each point. Do that and
4. sec(x)+xsec(x)tan(x) 9. -csc^2(x)/[1+cot(x)] -csc^2(x)cot(x)/[1+cot(x)]^2 11. y = -x+3+(pi) 13. x=3what? 18. dy/dx of tan(x) = sec^2(x) and function keeps increasing from zero dy/dx of cot(x)
First of all, to avoid confusion, you should write it y = (1/4)x+6 That's the equation for a straight line so it only takes two points to plot it. Just put in a value for x, calculate y, and plot (x
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