Abe Mantell - Calculus - Homework/Study Tips - Teens

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Expert Profile: Abe Mantell

Expertise: Hello, I am a college professor of mathematics and regularly teach all levels from elementary mathematics through differential equations, and would be happy to assist anyone with such questions!

Experience in the area
Over 15 years teaching at the college level.

Organizations
NCTM, NYSMATYC, AMATYC, MAA, NYSUT, AFT.

Education/Credentials
B.S. in Mathematics from Rensselaer Polytechnic Institute
M.S. (and A.B.D.) in Applied Mathematics from SUNY @ Stony Brook

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Average Ratings
Prestige Points: 14580
Knowledge	9.86 Best of the best
Clarity of Response	9.83 Best of the best
Timeliness	9.95 Best of the best
Politeness	9.96 Best of the best
Number Of Questions (in Past 24 Hours)		0
Max Questions to be Asked (in 24 Hour period)		1
Total Questions (since joining AllExperts)		400

Recent Reviews from Users

Knowl	Clarity	Time	Politeness	Date
10	10	10	10	09/02/08
10	10	10	10	09/02/08
10	10	10	10	07/21/08
10	10	10	10	07/19/08
10	10	10	10	07/21/08

User Comments

I see it now and I feel sort of stupid lol. Thank you very much for the insight, now I see how polar and rectangular are related.
(John Arthur on 09/02/08)

Thank you!
(Lisel on 07/21/08)

Very prompt and helpful answer! Thank you Franco Vivona
(FrancoVivona on 07/19/08)

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Recent Answers from Abe Mantell

2008-09-02 describing level curves using polar coordinates.: Hello John, Polar form often helps one sketch and understand a complicated function. It is not all that obvious what the level curves of f(x,y) look like in rectangular form, but in Polar form......

2008-07-24 finding the derivative: Hello Kiko, The usual way to take the derivative of this would be via the quotient rule. Thus, a. f'(x)=[(4x-8)'(x^2+5x-14)-(4x-8)(x^2+5x-14)']/(x^2+5x-14)^2 --- = [4(x^2+5x-14)-(4x-8)(2x+5)]/(x^2+5x-14)^2...

2008-07-19 Calculus applications: Hello Franco, It is always satisfying to hear from people who develop an appreciation for or interest in mathematics after having shunned it during the early years! :-D As for calculus with applications...

2008-07-09 differentiation: Hello Aliya (nice name)! Let f(x)=x^(5/2), thus: f'(x)=limit(h->0) [(x+h)^(5/2) - x^(5/2)]/h now multiply by [(x+h)^(5/2) + x^(5/2)]/[(x+h)^(5/2) + x^(5/2)] (i.e. the conjugate of (x+h)^(5/2) - x^(5/2))...

2008-07-08 Related Rates: Hello Stephanie, Since h is constant, dh/dt=0 and no need to treat h as a variable. So, V=L*W*10 or V=10LW...now differentiate w.r.t. "t"... ==> dV/dt= 10(L*dW/dt + dL/dt*W), product rule since both...