Calculus/Expert Profile

Average Ratings

• Knowledgeability 9.88
• Clarity of Response 9.82
• Timeliness 9.91
• Politeness 9.97

• Number of Questions (in Past 24 Hours) 0
• Max Questions to be Asked (in 24 Hour Period) 1
• Total Questions (since joining AllExperts) 448
• Volunteer Since 2003-04-30
• Prestige Points 15280

Recent Reviews from Users

Read More Comments

    K = Knowledgeability    C = Clarity of Response    T = Timeliness    P = Politeness

User	Date	K	C	T	P	Comments
Warm	08/14/09	10	10	10	10	Thanks
Jason	07/22/09	10	10	10	10	Thank you
shikhin	07/20/09	10	10	10	10	Thanks a lot....got the point.....I .....
Jason	07/09/09	10	10	10	10	Thank you very much
Attir	07/09/09	10	10	10	10	very nice i really appriciate your fast .....

Recent Answers from Abe Mantell

2009-08-14 Trigonometry show part:

Hello from the US! :-) Use the sum and difference formulas for tangent: tan(30+a)=[tan(30)+tan(a)]/[1-tan(30)tan(a)]=[sqrt(3)+3tan(a)]/[3-sqrt(3)tan(a)] tan(60-a)=[tan(60)-tan(a)]/[1+tan(60)tan(a)]=[sqrt(3)-tan(a)]/[1+sqrt(3)tan(a)]

2009-08-11 Calculus:

Hello, Since (1,6) satisfies y=ax^2+bx+c, we get: 6=a+b+c...since the tangent line at x=1 is horizontal, that means the turning point is at x=1 (and y=6), so we can write the parabola as y=a(x-1)^2

2009-07-21 Maximizing Area:

Since the area of a triangle can be written as: A=(1/2)(a)(b)sin(C), where C is the angle between the two sides. So, the maximum area will be when sin(C) is as large as possible. Thus, C=90 degrees

2009-07-20 3rd Derivative:

1. What is happening to f(x) or f''(x)??? 2. You want to maximize f'''(x)? So, take the derivative of f'''(x), . which is f''''(x)=24, but f''''=24 and is never zero. So the . maximum and minimum

2009-07-16 calculus:

1. y=x^2-2x has vertex at x=-b/(2a)=2/2=1, so x=1 and y=-1 ==> (1,-1) 2. Basically, if you arrange the equation for a parabola in this form: (x-h)^2=4p(y-k) The vertex is (h,k); the focus is (h, k+p)