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I can provide good answers to questions dealing in almost all of mathematics especially from A`Level downwards. I believe i would be very helpful in calculus and can as well help a good deal in Physics with most emphasis directed towards mechanics.
An engineering graduate. I have been doing maths and physics all my life.
| User | Date | K | C | T | P | Comments |
|---|---|---|---|---|---|---|
| Anthony | 11/20/09 | 10 | 10 | 10 | 10 | Thank you!!! |
| Cindy | 11/18/09 | 10 | 10 | 10 | 10 | Thank you! |
| Patty | 11/13/09 | 10 | 10 | 10 | 10 | |
| Mohammed | 11/12/09 | 10 | 10 | 10 | 10 | |
| mikel | 11/11/09 | 10 | 10 | 10 | 10 | The steps were perfect. I am able ..... |
Hi Lauren, In the first part, there were no xy terms and it was straightforward to differentiate. We differentiate the term and add x'(i.e dx/dt) or y' as appropriate. In the second part, there is an
Hi Cindy, cos²θ + sin²θ = 1 sin²θ = 1 - cos²θ sinθ = √(1 - cos²θ) But, cosθ = 3/5 So, sinθ = √[1 - (3/5)²] = √[1 - (9/25)] =
Hi Patty, y = √x . e^x² . (x² + 2)^10 Taking logarithms, ln y = ln[√x . e^x² . (x² + 2)^10] ln y = ln√x + ln(e^x²) + ln(x² + 2)^10 ln y = (1/2)ln x + x²ln(e) + 10ln(x² + 2) ln y
Hi Alicia, The formula for the area A of a rectangle with length l and width w is A = lw differentiating with respect to time t, dA/dt = l.dw/dt + w.dl/dt dl/dt = 8cm/s dw/dt = 3cm/s l = 20cm w
Hi Steve, Well, i'm afraid that in this case both d²V/dr² and d³V/dr³ dont actually represent any physical quantity. But of course that is not to say that they dont have any significance, they actually

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