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Dr. Nyayapati Swami

Singapore
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Expertise

I can help you in solving first and second order differential equations. Questions must be at the Undergraduate level. Do not expect me to do all your homework.. If you have a homework question with no clues on how to go about, I will only give you some pointers on solving them.

Experience in the area

Ph.D. in Mathematics with more than 20 years of teaching.
In addition to undergraduate calculus, I taught many more advanced subjects like Complex Analysis, General Topology, Numerical Analysis, Operations Research, Graph Theory, Mathematical Analysis, Mathematical Economics, Optimisation Theory.

Education/Credentials

Ph.D. (University of Toledo, USA)

What do you like about this subject?

Differential equations have applications in many areas. One can solve many real life problems using methods of differential equations.

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Recent Answers from Dr. Nyayapati Swami

2012-04-24 Matrices and Determinants Elements:

Yes, the elements can be any real or complex numbers. In fact, one can consider matrices with elements from any Field. (In mathematics, a field is an algebraic structure more general than real or complex

2012-03-18 F/U to my Maximum Principle question...:

Hi Joe,  I am not an expert in this area (Pdes) that is why I rejected your question. If you still insist, then let me give you my view:    The way the maximum principle works is first show that the maximum

2011-07-29 Power series solution for differential equation:

Replacing x by x+1 changes to eqn to  dy/dx = 2/(x+1) + 3 - (x + 1)^2   [note dy/d(x+1) = dy/dx)    Expand  2/(x+1) into a power series (powers of x):  2/(x+1) = 2 (1 - x + x^2 - x^3 + .... )  (x + 1)^2

2011-03-04 Autonomous Nonlinear System of ODE:

x^3=2y^3=2(2x^3)=4x^3  x^3 - 4x^3 = 0  -3x^3=0  x=0  So x=0, y=0 is the only critical point of the system.  If you want to study further, you can find particular solutions:    The function y(t) = 0 satisfies

2011-02-28 concave functions:

A function f(x) is concave if its second-order derivative f''(x) is negative.  In your example, y = a x^b, therefore   dy/dx = abx^(b-1) and  the second derivative is  d^2y/dx^2 = a b (b-1) x^(b-2)  Since

 

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