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Differential Equations/Expert Profile
Expertise
I can help you in solving first and second order differential equations. Questions must be at the Undergraduate level. Do not expect me to do all your homework.. If you have a homework question with no clues on how to go about, I will only give you some pointers on solving them.
Experience in the area
Ph.D. in Mathematics with more than 15 years of teaching.
In addition to undergraduate calculus, I taught many more advanced subjects like Complex Analysis, General Topology, Numerical Analysis, Operations Research, Graph Theory, Mathematical Analysis, Mathematical Economics, Optimisation Theory.
Education/Credentials
Ph.D. (University of Toledo, USA)
What do you like about this subject?
Differential equations have applications in many areas. One can solve many real life problems using methods of differential equations.
Average Ratings
Recent Answers from Dr. Nyayapati Swami
2009-10-06 Ordinary Differential Equation:
This is a standard question and can be solved directly by applying the formulae. No special skills are needed to answer this question. I will just give you some clues and you need to work out the details
2009-10-01 nonhomogeneous differential equation:
This is a very standard question, you can find the method of solving in any textbook. solve the characteristic eqn: y = 1 + i sqrt(3), y = 1 - i sqrt(3) Complementary function (CF) CF = e^x
2009-09-29 differential equations:
Let v = cosy Then dv/dx = - siny dy/dx = - cosy (1 - xcosy) = - v(1-xv) Now let u = 1/v (or you could have chosen u = secy in the beginning) Then du/dx = - (1/v^2) dv/dx
2009-09-18 Math/econ:
This requires the knowledge of derivatives. Point elasticity of demand = (P/Q) dQ/dP Since your demand is Q = 120 - P, you have dQ/dP = -1 Therefore, point elasticiy = (P/Q)(-1) = -P/Q You are given
2009-08-30 Differential equations:
PN = y PN/TN = dy/dx y/TN = dy/dx TN = y / (dy/dx) Area of the triangle = tanx (1/2)(PN)(TN) = tanx (1/2)(y) (y / (dy/dx)) = tanx (1/2) y^2 = tanx (dy/dx) dy/dx = (1/2) y^2 / tanx dy/dx = (1/2)
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