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I can answer almost anything that is sent in. If I can't, I'll let you know, but I don't expect that to happen much.
I have known about it since the mid 80's. There were a few questions in Number Theory in this software. I have answered several thousand other questions in mathematics.
MS in Mathematics at Oregon State, BS in Mathematics at Oregon State.
I graduated with honors in Mathematics when gettin my BS and MS.
People at OSU
It seems so abstract
| User | Date | K | C | T | P | Comments |
|---|---|---|---|---|---|---|
| TJ | 11/07/09 | 10 | 10 | 10 | 10 | |
| Andrew | 10/05/09 | 7 | 7 | 10 | 10 | I am satisfied with the answer. Thanks ..... |
| Asad | 09/25/09 | 10 | 10 | 10 | 10 | Thank you |
1) If |x-2|<δ, then |2x-4|<ε, ε = 0.01. Looking at |x-2| and |2x-4|, it can be seen that |2x-4| = |2(x-2)|, so the 2nd is twice the 1st. If ε = 0.01, δ is the is half of ε
g(n) = summation (over d|n) (mew(d)f(n|d)); show f(n) summartion(over d|n) of g(d) questions: what is the mobius function? Suppose n is 10; does this mean that d is taken as 1, 2, 5, and 10?
No, I don't know what the thing to look at would be. Maybe you could use how far the rabbit runs in a day. Maybe it could be how long each one stays in the barn. Those both sound like good approaches
For xn->a, for n=k large enough, this means that for n>=k, all |xn - a| < ε for any ε however close to 0. At this point, 1/x is between 1/(x-ε) and 1/(x+ε). Take |1/(x-ε
It almost looked like |xn| was the absolute value of |xn|, but this can easily be disproved. What is really meant, I belive is the function of the limit as n-> ∞ of the terms is the same as

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