You are here:

Number Theory/Expert Profile


Ask A Question

Expertise

I can answer almost anything that is sent in. If I can't, I'll let you know, but I don't expect that to happen much.

Experience in the area

I have known about it since the mid 80's. There were a few questions in Number Theory in this software. I have answered several thousand other questions in mathematics.

Education/Credentials

MS in Mathematics at Oregon State, BS in Mathematics at Oregon State.

Awards and Honors

I graduated with honors in Mathematics when gettin my BS and MS.

Past/Present Clients

People at OSU

What do you like about this subject?

It seems so abstract

Average Ratings

Recent Reviews from Users

Read More Comments

    K = Knowledgeability    C = Clarity of Response    T = Timeliness    P = Politeness
UserDateKCTPComments
TJ11/07/0910101010 
Andrew10/05/091010I am satisfied with the answer. Thanks .....
Asad09/25/0910101010Thank you

Recent Answers from Scott A Wilson

2009-10-19 math:

1) If |x-2|<δ, then |2x-4|<ε, ε = 0.01. Looking at |x-2| and |2x-4|, it can be seen that |2x-4| = |2(x-2)|, so the 2nd is twice the 1st. If ε = 0.01, δ is the is half of ε

2009-10-15 mobius inversion:

g(n) = summation (over d|n) (mew(d)f(n|d)); show f(n) summartion(over d|n) of g(d) questions: what is the mobius function? Suppose n is 10; does this mean that d is taken as 1, 2, 5, and 10?

2009-10-08 theory used to estimate pumkin seeds:

No, I don't know what the thing to look at would be. Maybe you could use how far the rabbit runs in a day. Maybe it could be how long each one stays in the barn. Those both sound like good approaches

2009-10-07 One more question, advanced calculus:

For xn->a, for n=k large enough, this means that for n>=k, all |xn - a| < ε for any ε however close to 0. At this point, 1/x is between 1/(x-ε) and 1/(x+ε). Take |1/(x-ε

2009-10-07 proof, advanced calculus:

It almost looked like |xn| was the absolute value of |xn|, but this can easily be disproved. What is really meant, I belive is the function of the limit as n-> ∞ of the terms is the same as

 

Ask A Question

All Answers

Answers by Expert:


Ask Experts

Volunteer


©2009 About.com, a part of The New York Times Company. All rights reserved.