I can answer all questions up to, and including, graduate level mathematics. I am more likely to prefer questions beyond the level of calculus. I can answer any questions, from basic elementary number theory like how to prove the first three digits of powers of 2 repeat (they do, with period 100, starting at 8), all the way to advanced mathematics like proving Egorov's theorem or finding phase transitions in random networks. I do not understand why Number Theory is not included in "Advanced Mathematics."
I am a PhD educated mathematician working in research at a major university.
Various research journals of mathematics. Various talks & presentations (some short, some long), about either interesting classical material or about research work.
BA mathematics & physics, PhD mathematics from a top 20 US school.
Various honors related to grades, various fellowships & scholarships, awards for contributions to mathematics and education at my schools, etc.
In the past, and as my career progresses, I have worked and continue to work as an educator and mentor to students of varying age levels, skill levels, and educational levels.
|Harry||09/25/14||10||10||10||Simply the best!|
|Becky||11/14/12||10||10||10||Thank a trillion! So far no one .....|
You are missing the decimal point: 31.500 = 11111.100 31.625 = 11111.101 The number "31.5" is not an integer, but you seemed to think it was equal to "11111100" which is an integer (no decimal
This is an old, and somewhat "cheesy," riddle. The first line is 3. Now what do you see? You see one 3. That gives the second line, 13. What do you see? You see one 1 and one 3. That gives
This is a complicated question - what makes the question hard to answer is the use of the word "why" -- it is one thing to say "can you show me that there are irrational numbers between 0 and 1?" but it
I assume the best possible resource would be the references listed in the Wikipedia article. This result is, as far as I can tell, a major pin in the theory of numbers, so it may not be mentioned or explained
Every pair produces three more pairs. You start with two pairs: (2,1), (3,1) Then each pair spawns three more pairs: (m,n) = (2,1) gives the following: (2m-n,m) = (3,2) (2m+n,m) = (5,2) (m+2n