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I can answer questions in basic algebra and any grade school math.
Love math, currently helping my nephew get through Intermediate Algebra.
I majored in Math Ed in college (but decided not to teach), so have over 40 credits of math.
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The only way I know is with a lot of pencil work. You just whittle it down. 10^3 is 1000 so you know it's more than that. 20^3 is 8000, so you know it's between 10 and 20 and it's a little closer to
Going on the assumption that the problem is accurate as I applied the parentheses 5-(1 1/2)X=-9 5-(3/2)X=-9 multiply everything by 2 10-3x = -18 add 3x and 18 to both sides of = sign 10-3x +3x
to write two equivalent ratios, just multiply 7 and 4 by any two numbers. 2 and 3 are easiest, so 7:4 = 14:8 = 21:12 To reduce, just treat the ratios as a fraction and reduce them like you would a fraction
Oh, that I understand. 2mg instead of .2mg. That's a 900% increase. As an aside, unfortunately, this happens all too often. A lot of the time because the pharmacist cannot read the DRs handwriting
No, actually, that's the good thing about multiplying fractions, you don't have to worry about common denominators. 1/2 times 3/4 = 3/8. If you made the denominators the same, then you'd have to reduce
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