Basic Math/Expert Profile


Ask A Question

Expertise

When I work through problems, I emphasize principles and key ideas which I believe are worth noting. I will try to answer questions in the following areas, but not at the advanced level. Algebra. Sequences & Series. Trigonometry. Functions & Graphs. Coordinate Geometry. Quadratic Polynomials. Exponentials & Logarithms. Basic Calculus. Probability, Permutations and Combinations. Mathematical Induction. Complex numbers. Physics problems.

Experience in the area


Experience:
I have worked as a teaching assistant in college. My hope is that more people will share knowledge without boundary, give help without seeking recognition or monetary rewards.

Supplementary Website:
See a selection of past questions in my maths repository under "Question Archive"

Education Credentials:
Bachelor degree in Engineering Science.


"Everyone struggles with something."

Something interesting about this subject that others may not know:

.

Average Ratings

Recent Reviews from Users

Read More Comments

    K = Knowledgeability    C = Clarity of Response    T = Timeliness    P = Politeness
UserDateKCTPComments
Kenneth11/20/0910101010Thanks
Richard11/20/0910101010Josh, thanks i'm just reading up on .....
Richard11/18/0910101010Josh, thanks for all your help and .....
William11/13/0910 
faizel11/12/09 

Recent Answers from Josh

2009-11-21 Weighted Average:

Hi Dennis, There are many ways to compute the weighted average. Basically, the only mathematical requirement is that the weights all add up to one. I can say that the equation you gave is proper, since

2009-11-20 completing the square in quadratic equations,cubic equations,graphs:

Edited: - Q2 | Relationship between the a,b,c,d coefficients of a cubic polynomial and its roots p,q,r. | Putting minus sign back into equations which involve "b" and "d" | This has no impact on subsequent

2009-11-19 Percentages & Fractions:

I think what we looked at last time is not unrelated to the question that you now pose. Recapping on what we have done -- previously, we considered the problem of finding a multiplicative factor (X/Y)

2009-11-19 cube:

Let the cube root of 5000 be x. What this means is that x*x*x = 5000. This is not a pleasant number to work out in the head. To find x, may I suggest that you compute (5000)^(1/3) on a calculator.

2009-11-17 partial fractions:

Hi Richard, For Q1, (x^3+1)/(x^2+1) = Ax + B + C/x + D/(x^2+1), write LHS numerator as (x^3+x-x+1) = x(x^2+1) -x+1. This gives [x(x^2+1)-x+1]/(x^2+1) = x + (-x+1)/(x^2+1) = Ax + B + C/x + D/(x^2+1)

 

Ask A Question

All Answers

Answers by Expert:


Ask Experts

Volunteer


©2009 About.com, a part of The New York Times Company. All rights reserved.