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When I work through problems, I emphasize principles and key ideas which I believe are worth noting. I will try to answer questions in the following areas, but not at the advanced level. Algebra. Sequences & Series. Trigonometry. Functions & Graphs. Coordinate Geometry. Quadratic Polynomials. Exponentials & Logarithms. Basic Calculus. Probability, Permutations and Combinations. Mathematical Induction. Complex numbers. Physics problems.
Experience:
I have worked as a teaching assistant in college. My hope is that more people will share knowledge without boundary, give help without seeking recognition or monetary rewards.
Supplementary Website:
See a selection of past questions in my maths repository under "Question Archive"
Education Credentials:
Bachelor degree in Engineering Science.
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| User | Date | K | C | T | P | Comments |
|---|---|---|---|---|---|---|
| Kenneth | 11/20/09 | 10 | 10 | 10 | 10 | Thanks |
| Richard | 11/20/09 | 10 | 10 | 10 | 10 | Josh, thanks i'm just reading up on ..... |
| Richard | 11/18/09 | 10 | 10 | 10 | 10 | Josh, thanks for all your help and ..... |
| William | 11/13/09 | 9 | 7 | 8 | 10 | |
| faizel | 11/12/09 | 8 | 8 | 9 | 8 |
Hi Dennis, There are many ways to compute the weighted average. Basically, the only mathematical requirement is that the weights all add up to one. I can say that the equation you gave is proper, since
Edited: - Q2 | Relationship between the a,b,c,d coefficients of a cubic polynomial and its roots p,q,r. | Putting minus sign back into equations which involve "b" and "d" | This has no impact on subsequent
I think what we looked at last time is not unrelated to the question that you now pose. Recapping on what we have done -- previously, we considered the problem of finding a multiplicative factor (X/Y)
Let the cube root of 5000 be x. What this means is that x*x*x = 5000. This is not a pleasant number to work out in the head. To find x, may I suggest that you compute (5000)^(1/3) on a calculator.
Hi Richard, For Q1, (x^3+1)/(x^2+1) = Ax + B + C/x + D/(x^2+1), write LHS numerator as (x^3+x-x+1) = x(x^2+1) -x+1. This gives [x(x^2+1)-x+1]/(x^2+1) = x + (-x+1)/(x^2+1) = Ax + B + C/x + D/(x^2+1)
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